• 如何证明|OA|·|OB|=|OT|2PD=DM,PC+PD+CD=HM.如果存在另外的C',D',可同样证明得PC'+PD'+C'D'=C'H+C'D'+D'M但由两点之间直线距离最短,可得PC'+PD'+C'D'<PC+PD+CD.如何证明|OA|·|OB|=|OT|2...
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